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Hatshy [7]
4 years ago
7

When do two different position-time graphs have matching velocity-time graphs?

Physics
1 answer:
Ivan4 years ago
8 0

Answer:

when they have the same slope

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Help needed
MakcuM [25]

Answer: Atmosphere and geosphere.

Geo-sphere is the solid part of the earth. Hydrosphere is the water part. The living things on the earth make up the biosphere. The gases, water vapors etc make up the atmosphere. When a volcanic eruption adds carbon dioxide to the air, the carbon-dioxide is being added from geosphere to the atmosphere. Hence, there is interaction between atmosphere and geosphere.

6 0
4 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
PilotLPTM [1.2K]

Answer:

859.07 N

Explanation:

u = Initial velocity = 1.9 m/s

v = Final velocity

s = Displacement = 0.165 m

a = Acceleration

m = Mass = 890 kg

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-1.9^2}{2\times 0.165}\\\Rightarrow a=-10.93\ m/s^2

Force

F=ma\\\Rightarrow F=870\times -10.93\\\Rightarrow F=859.07\ N

The magnitude of the average force on the bumper is 859.07 N

4 0
3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

6 0
3 years ago
You are taking care of two small children, Sarah and Rachel, who are twins. On a nice cool, clear day you decide to take them ro
BlackZzzverrR [31]

Answer:

Explanation:

Rachel and Sarah are standing on horizontal ground . Let T₁ be the tension between Rachel and Sarah and Sarah is in between you.

Force = mass x acceleration

Apply this equation on Rachel

T₁ = 23 x 2 = 46 N

Let T₂ be tension between Sarah and me and it is inclined at 60°

Force = mass x acceleration

Apply this equation on Sarah

T₂ cos 60 - T₁ = 23 X 2 = 46

T₂ cos 60 - 46 =46

T₂ cos 60  = 92

T₂ = 92 / .5

= 184 N

5 0
3 years ago
Read 2 more answers
A 68 kg runner exerts a force of 59N. What is the acceleration of the runner?
Korvikt [17]

Explanation:

<em><u>Newton's First Law ,</u></em>

F = ma

a = m/F

a = 68 / 59

a = 1.15 m/s2

4 0
3 years ago
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