Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Answer:
C. (6,2)
Step-by-step explanation:
(-2,-3) becomes (-2+8, -3+5), (6,2)
The answer is √3. This is because √3 is already an irrational number and if you multiply it but either -5/9 or add it by 4, the product or sum will not terminate, nor repeat, or is able to turn in to a fraction
Answer:
35
Step-by-step explanation:
x-18=y
y*-3=-51
y=17
x-18=17
17+18=x
x=35
Answer:
intervals (-3,-1) and (0,+infinity)
Step-by-step explanation:
if f'(x)>0 then f is increasing
