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The figure shown in the picture is a rectangular shape that is missing a triangular piece. To determine the area of the figure you have to determine the area of the rectangle and the area of the triangular piece, then you have to subtract the area of the triangle from the area of the rectangle.
The rectangular shape has a width of 12 inches and a length of 20 inches. The area of the rectangle is equal to the multiplication of the width (w) and the length (l), following the formula:
For our rectangle w=12 in and l=20 in, the area is:
The triangular piece has a height of 6in and its base has a length unknown. Before calculating the area of the triangle, you have to determine the length of the base, which I marked with an "x" in the sketch above.
The length of the rectangle is 20 inches, the triangular piece divides this length into three segments, two of which measure 8 inches and the third one is of unknown length.
You can determine the value of x as follows:
x=4 in → this means that the base of the triangle is 4in long.
The area of the triangle is equal to half the product of the base by the height, following the formula:
For our triangle, the base is b=4in and the height is h=6in, then the area is:
Finally, to determine the area of the shape you have to subtract the area of the triangle from the area of the rectangle:
The area of the figure is 228in²
Answer:
The estimated amount of metal in the can is 87.96 cubic cm
Step-by-step explanation:
We can find the differential of volume from the volume of a cylinder equation given by
Thus that way we will find the amount of metal that makes up the can.
Finding the differential.
A small change in volume is given by:
So finding the partial derivatives we get
Evaluating the differential at the given information.
The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.
On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.
Replacing all those values on the differential we get
That give us
Or in decimal value
Thus the volume of metal in the can is 87.96 cubic cm.