If 22.50 mL of a sodium hydroxide solution is necessary to neutralize 18.50 mL of a 0.1430 M HNO3 solution, what is the concentr

Question

Troyanec [42]

4 years ago

10

If 22.50 mL of a sodium hydroxide solution is necessary to neutralize 18.50 mL of a 0.1430 M HNO3 solution, what is the concentr

ation of the NaOH? (Report your answer in molarity.)

Chemistry

1 answer:

Nataliya [291] · Answer 1 · 2021-12-26T10:01:23+03:00

The concentration of NaOH is calculated as follows

calculate the moles of HNO3

moles =molarity x volume
=18.50 x0.1430 = 2.6455 moles

write the reacting equation
that is
NaOH + HNO3 =NaNO3 +H2O
by use mole ratio between NaOH: HNO3 the moles of NaOH is also 2.6455moles

concentration is therefore moles/volume
= 2.6455/ 22.50 = 0.118M