Answer: c. Salt and Water
Explanation:
For example;
When an Arrhenius acid such as; Tetraoxosulphate (VI) acid (H2SO4) reacts with an Arrhenius base such as Potassium hydroxide (KOH), the products formed in this neutralization reaction is a salt known as ''Potassium Sulphate'' (K2SO4) and ''Water'' (H2O).
H2SO4 + KOH -------------> K2SO4 + H2O
A is the reasonable answer
I believe the end result is still 83 moles since there is never an amount of sulfur atoms added to the initial amount, but rather oxygen and water is repeatedly added to it. To find it's weight, first find the molar mass of H2SO4:
H2 + S + O4 = 2.00 + 32.1 + 64.0 = 98.1 g/mol
and mass = (98.1 g/mol)(83 mol) = 8142.3 g
rounded to 8.1 x 10^3 g assuming 100% yield?
