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3 years ago

0.1-3=5 find mia's mistake

Mathematics

1 answer:

EleoNora [17]3 years ago

7 0

Answer:

1-3=5 does not equal what it is supposed to.

1-3=-2. So mia is completely wrong.

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A=1+Prt solve for p

lilavasa [31]

$A=1+Prt\\\\Prt=A-1\\\\P=\dfrac{A-1}{rt}$

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3 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

Janet earns 7.55 per hour mowing lawns. Kelsey earns twice that amount per hour babysitting and ty earns 1.25 less per hour than

Artemon [7]

Janet = 7.55 x 15(hours) = 113.25
Kelsey = 15.10 x 15(hours) = 226.50
Ty = 13.85 x 15(hours) = 207.76

To gets Kelsey’s wage per hour you do 7.55 x 2 and to get ty you do 15.10(Kelsey’s wage per hour) - 1.25 which is 207.76

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3 years ago

Find the next two terms for the following pattern 1, -2, 2, -4, 0

Oxana [17]

After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1

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2 years ago

Mrs. Parson baked 30 cookies. 5 sixths of the cookies were oatmeal. How many oatmeal cookies did Mrs. Parson bake?

vekshin1

She cooked 25 cookies because 5/6 =25/30 because you multiply each number by 5 and it becomes 25/30. Hope this helped

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3 years ago

Read 2 more answers