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andrew-mc [135]
3 years ago
14

158.297 rounded each number to the nearest while number

Mathematics
1 answer:
Katarina [22]3 years ago
5 0

Answer: 158

Step-by-step explanation:

158.297

It rounds to 158

since 0.297 < 0.5

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The length of a rectangle is 2m-1 and the width is m+3. Simplify an expression for the perimeter of the rectangle.
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6m+ 4

Step-by-step explanation:

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Step-by-step explanation:

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Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
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<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

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Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

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3 years ago
In the coordinate plane, three vertices of rectangle abcd are a(0, 0, b(0, a, and d(b, 0. what are the coordinates of point c?
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So the point would be c)0,0
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