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love history [14]
3 years ago
7

30PTS only answer if you know please!

Mathematics
1 answer:
Archy [21]3 years ago
8 0
The expression inside the absolute value can be either positive or negative.

above, they solved for x in the positive expression. x/2 + 3 = 2

solve for x in the negative expression.
x/2 + 3 = -2
x/2 = -2 - 3
x/2 = -5
x = -10
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Find the midpoint between (-1+9i) and B=(5-3i)
sdas [7]

Answer:

2 + 3i, midpoint is (2,3)

Step-by-step explanation:

we need to find the midpoint between (-1+9i) and B=(5-3i)

To find the midpoint of two points (a+bi)  and (c+di) in a complex plane,  

we apply formula

\frac{a+c}{2} + \frac{b+d}{2} i

A = (-1+9i) and B=(5-3i)

Midpoint for AB is

\frac{-1+5}{2} + \frac{9+(-3)}{2}i

\frac{4}{2} + \frac{6}{2}i

2 + 3i , so midpoint is (2,3)


8 0
3 years ago
Read 2 more answers
How many names are for square
muminat
There are about four other names for a square.
3 0
3 years ago
Read 2 more answers
B/65 = 7/13 <br><br> show work please
Ludmilka [50]

Answer: b/65=7/13

65/13=5

35/7=5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
3 (x - 3) + x (r + 4)
docker41 [41]

Answer:

Step-by-step explanation:

3(x-3)+x(r+4)

3x-9+xr+4x

7x+9+xr

7 0
3 years ago
find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
Tomtit [17]

Answer:

y = -2x^2(x - 3)

Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

0 = a*3^2(3 - h)

0 = 9a (3 - h)

0 = 27a - 9ah

from which h = 3

<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

3 0
3 years ago
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