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NNADVOKAT [17]
3 years ago
7

Twenty-four thousandths as a decimal

Mathematics
2 answers:
rewona [7]3 years ago
7 0
0.024 hope this helped
lozanna [386]3 years ago
7 0
The answer is 0.024
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Given the system below, which points are solutions? (check all that apply)
LuckyWell [14K]
It’s 3.46 and 6.64hrhss
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3 years ago
What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
nikklg [1K]

Answer:

The value of the expression increases as j decreases

Step-by-step explanation:

Let f(j) = 150 - j150 - j150

f(j) = 150 - j300

As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.

For example:

When j = 1, f(j) = 150 - (300*1) = -150

When j = 0.5, f(j) = 150 - (300*0.5) = 0

When j = 0. f(j) = 150 - (300*0) = 150

It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases

4 0
3 years ago
PLEASE HURRY!! <br> simplify completely<br> show all work for full credit
Irina18 [472]

Answer:

4x^{3}

Step-by-step explanation:

<u>Given:</u>

(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}

<u>Apply exponent rule of distribution:</u>

\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the numerator:</u>

\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the denominator:</u>

\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}

<u>Simplify:</u>

4x^{3}

-> To explain this party since it is a bigger jump, 3^{\frac{1}{3}}x is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have x^{3} leftover too.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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2 years ago
Factor y=x Squared-8x
Minchanka [31]
X²-8x
factor out x
x(x-8)
y=x(x-8)
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3 years ago
Find the measure of the arc
steposvetlana [31]

The answer is kindly 21 (100% correct)

3 0
2 years ago
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