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Archy [21]
4 years ago
13

A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘ C . How many grams of this gasoline would fill a 12.8 gal tan

k ( 1US gal=3.78L )?
Chemistry
1 answer:
In-s [12.5K]4 years ago
6 0
To answer this question, you need to know how to convert milliliters into liter then into a gallon. In this question, you are given the gasoline density (0.737g/ml) and the volume (12.8gallon). The information is enough to determine the gas weight. The calculation would be:

Gas weight= density * volume
Gas weight= 0.737g/ml * 12.8 gal * 3.78L/gal * 1000ml/L= 35659.008 grams
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Answer:

The correct answer is  

[CH4][H2O]/[CO][H2]3

Option 3 is correct

Explanation:

Step 1: Data given

For the equation aA + bB ⇆ cC + dD

The equilibrium constant is [C]^c * [D]^d / [A]^a*[B]^b

Step 2: Calculate the equilibrium constant Kc

CO+3H2⇌CH4+H2O

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The correct answer is  

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Option 3 is correct

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