More drag is created because the air molecules are not moving out of the way of the airplane
Answer:
Preparation and Standardization of 0.1 M Ferrous Ammonium...
Dissolve 40 g of ferrous ammonium sulfate in a previously cooled mixture of 40 ml of sulphuric acid and 200 ml of water.
Dilute with sufficient freshly boiled and cooled water to produce 1000 ml.
Standardize the solution in the following manner.
Explanation:
Answer:
Henry Moseley.
Explanation:
Hello,
Henry Moseley's work stated that it is better to organize the periodic table in the light of the atomic number (which accounts for the amount of protons and electrons) instead of the atomic mass, because atomic numbers are not arbitrarily assigned as long as they have the aforesaid physical basis.
Best regards.
Answer:
Explanation:
A sound knowledge of specific heat capacity of the metals is required in this case.
The specific heat capacity of a metal is the quantity of heat required to the raise the temperature of a unit mass of it by 1°C.
It is related to quantity of heat using the expression below;
H = m c Δt
where m is the mass
c is the specific heat capacity
Δt is the temperature change
let us make the specific the subject of the expression;
c = 
we can see that there is an inverse relationship between specific heat and temperature change.
The specific heat capacity of a body is an intensive property that is unique to the metal.
The higher the specific heat capacity, the lower the amount of temperature change in it.
Let us find the specific heat capacity of the given metals;
Aluminium 0.897J/gK
Iron 0.412J/gK
Silver 0.24J/gK
After the heat is supplied,
Silver > Iron > Aluminium in terms of temperature change
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
