1.) Air can be separated into its constituents such as oxygen, nitrogen etc.
2.) Air has a variable composition because at different places different amount of gases are present in air.
Red blood cells are formed in the red bone marrow of bones. Stem cells in the red bone marrow called hemocytoblasts give rise to all of the formed elements in blood. If a hemocytoblast commits to becoming a cell called a proerythroblast, it will develop into a new red blood cell.
1840 times lesser than
Explanation:
Robert A. Milikan from his experiment found that electrons carry exactly one unit of negative charge and that its mass is 1840 times lesser than the mass of a common hydrogen atom.
- Robert Milikan performed the oil drop experiment and was able to determine the charge on an electron.
- From Milikan's experiment, the relative mass of an electron was discovered to be about 1840 times lesser than the mass of a hydrogen atom.
- A normal hydrogen atom is a proton with an actual mass of 1.67 x 10⁻²⁷kg.
- Electrons weight 9.11 x 10⁻³¹kg which is 1840 less than the weight of a proton.
Learn more:
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Answer:
Explanation:
Length: Length is a measure of distance
Height:The measurement from base to top or (of a standing person) from head to foot.
Circumference:The enclosing boundary of a curved geometric figure, especially a circle
Perimeter: Length of the outline of a shape.
Diagonal:A line segment that goes from one corner to another, but is not an edge. So when we directly join any two corners (called "vertices") which are not already joined by an edge, we get a diagonal. Diagonals of Polygons.
Diameter: A straight line passing from side to side of any figure or body, through its center.
1) Data:
T₁ = <span>
21°C
</span>
<span>T₂ = 51°C.
</span>
<span>V₁ = V₂ = 15.6 L
</span>
<span>P₁ = 249 kPa.
</span>
<span>Pb = 269 kPa.
</span>
<span>Questions:
</span>
• n = ?
• P₂ = ?
• Will the tires burst at the peak temperature? Explain.
• To what pressure should the tire pressure be reduced before starting
the ride to avoid bursting of the tires in the desert heat? (Assume no
significant change in tire volume.)
Pi = ?
2) Formula:
PV = nRT
P₁ / T₁ = P₂ / T₂
3) Solution
i) n
P₁V₁ = nRT ⇒ n = P₁V₁ / [RT₁]
n = 249 kPa × 15.6 liter / [8.314 (liter-kPa / mol-K) × (21 + 273.15K) ] =
n = 1.588 mol
ii) P₂
P₂ = P₁ T₂ / T₁ = 249 kPa (50 + 273.15 K) / (21 + 273.15K) = 273.5 kPa
iii) Tires will burst, since P₂ > Pb
iv) Pi
Pi / T₁ = Pb / T₂
Pi = Pb T₁ / T₂ = 269 kPa (21 + 273.15K) / (50 + 273.15K) = 244.9 kPa
The pressure shoul to be reduced to less than 244.9 kPa before starting to avoid the <span> bursting of the tires in the desert heat.</span>