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Llana [10]
3 years ago
7

T(x)=70(.80)*+20 where x is the time in minutes and the T is the temperature in degree celsius . What is the initial temperature

of the coffee?
Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

The initial temperature of the coffee was 90°C.

Step-by-step explanation:

The function representing the temperature of the coffee after <em>x</em> minutes is:

T(x)=70\cdot(0.80)^{x}+20

T is the temperature in degree Celsius.

The initial temperature of the coffee will be at <em>x</em> = 0.

Compute the value of T (x) at x = 0 as follows:

T(x)=70\cdot(0.80)^{x}+20

T(0)=70\cdot (0.80)^{0}+20

        =70\times 1+20\\=70+20\\=90

Thus, the initial temperature of the coffee was 90°C.

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Montano1993 [528]

Answer:

A = 388.58 cm^2

Step-by-step explanation:

For a cone whose base has a radius R, and a hypotenuse S, the area is:

A = pi*R^2 + pi*R*S

Where pi = 3.14

In this case, we can see that the diameter is: 15cm

Then the radius, half of the diameter, is:

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A = 3.14*(7.5cm)^2 + 3.14*(9cm)*(7.5cm) = 388.575 cm^2

Rounding to two decimal places, we need to look at the third one, which is a five, so we need to round up:

A = 388.58 cm^2

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