All categories

3 years ago

Pls help asapp picture attached

Mathematics

2 answers:

dalvyx [7]3 years ago

8 0

Answer:

The answer to your question is x = 50

Step-by-step explanation:

Data

∠1 = 110°

∠3 = 2x + 10

Process

1.- Angle ∠1 and angle 3 are vertical angles so, they measure the same.

∠1 = ∠ 3

110 = 2x + 10

2.- Solve for x

Substract 10 in both sides

110 - 10 = 2x + 10 - 10

Simplify

100 = 2x

Divide by 2 both sides

100/2 = 2/2 x

Simplify and result

50 = x

Olin [163]3 years ago

3 0

Answer:

Step-by-step explanation:

Angle 1 is 110.

Angle 3 is 2x plus 10.

Angle 1 and 3 are vertically opposite angles.

And vertically opposite angles r equal.

Which means, angle 1=angle 3,and angle 2=angke 4.

Here we only Need angle 2 and 3.

Angke 2= angle 3.

Which is 2x plus 10=110.

Therefore 2x=110-10=100

Therefore x = 100÷2=50

There u have it ma'am.

You might be interested in

(d) If the perimeter of a rectangle is 32, then the length is 13 and the width is 3.

Stells [14]

Answer:

length = 10
width = 6

Step-by-step explanation:

Any pair of dimensions that total 16 will give a rectangle with a perimeter of 32.

P = 2(L +W)

32 = 2(L +W)

16 = L +W . . . . . . . divide by 2

This is true for L = 13 and W = 3. It is also true for L = 10 and W = 6, or any other pair of dimensions x and (16-x).

8 0

2 years ago

Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

3 years ago

If the point (x, y) is in Quadrant IV, which of the following must be true?

gayaneshka [121]

Answer:

Any coordinate point with (positive x, negative y)

4 0

2 years ago

The expressions 10/12(245b−365) and 2/3(3b+6) represent the lengths of the diagonals of parallelogram WXYZ. For what value of b

makkiz [27]

Answer:

b = 1.52

Step-by-step explanation:

Length of diagonals of a parallelogram = $\frac{10}{12}(245b - 365)$ and $\frac{2}{3}(3b+6)$

If the given parallelogram is a rectangle,

Length of the diagonals will be equal in measure,

Therefore, $\frac{10}{12}(245b - 365)=\frac{2}{3}(3b+6)$

245b - 365 = $\frac{12}{10}\times \frac{2}{3}(3b+6)$

245b - 365 = $\frac{4}{5}(3b+6)$

5(245b - 365) = 4(3b + 6)

1225b - 1825 = 12b + 24

1225b - 12b = 24 + 1825

1213b = 1849

b = $\frac{1849}{1213}$

b = 1.52

5 0

2 years ago

What is the slope of the line that passes<br> through<br> 0(-4, 8) and (5, 2)?

zlopas [31]

Answer:

(-8,-4) and (-2,5). at reflect on x axis

4 0

2 years ago