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joja [24]
3 years ago
13

Pls help asapp picture attached

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The answer to your question is x = 50

Step-by-step explanation:

Data

∠1 = 110°

∠3 = 2x + 10

Process

1.- Angle ∠1 and angle 3 are vertical angles so, they measure the same.

                         ∠1 = ∠ 3

                        110 = 2x + 10

2.- Solve for x

Substract 10 in both sides

                        110 - 10 = 2x + 10 - 10

Simplify

                             100 = 2x

Divide by 2 both sides

                             100/2 = 2/2 x

Simplify and result

                                 50 = x                        

Olin [163]3 years ago
3 0

Answer:

50

Step-by-step explanation:

Angle 1 is 110.

Angle 3 is 2x plus 10.

Angle 1 and 3 are vertically opposite angles.

And vertically opposite angles r equal.

Which means, angle 1=angle 3,and angle 2=angke 4.

Here we only Need angle 2 and 3.

Angke 2= angle 3.

Which is 2x plus 10=110.

Therefore 2x=110-10=100

Therefore x = 100÷2=50

There u have it ma'am.

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GarryVolchara [31]

Answer:

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Step-by-step explanation:

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<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>3</em><em>c</em><em> </em><em>-</em><em> </em><em>7</em>

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A Ferris wheel is 20 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position
pantera1 [17]

Answer:

233.48s  

3.84 min

Step-by-step explanation:

In order to solve this problem, we can start by drawing what the situation looks like. See attached picture.

We can model this situation by making use of a trigonometric function. Trigonometric functions have the following shape:

y=A cos(\omega t+\phi)+C

where:

A= amplitude =-20m because the model starts at the lowest point of the trajectory.

f= the function to use, in this case we'll use cos, since it starts at the lowest point of the trajectory.

t= time

\omega= angular speed.

in this case:

\omega=\frac{2\pi}{T}

where T is the period, in this case 6 min or

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so:

\omega=\frac{2\pi}{360}

\omega = \frac{\pi}{160}

and

\phi= phase angle

C= vertical shift

in this case our vertical shift will be:

2m+20m=22m

in this case the phase angle is 0 because we are starting at the lowest point of the trajectory. So the equation for the ferris wheel will be:

y=-20 cos(\frac{\pi}{180}t)+22

Once we got this equation, we can figure out on what times the passenger will be higher than 13 m, so we build the following inequality:

-20 cos(\frac{\pi}{180}t)+22>13

so we can solve this inequality, we can start by turning it into an equation we can solve for t:

-20 cos(\frac{\pi}{180}t)+22=13

and solve it:

-20 cos(\frac{\pi}{180}t)=13-22

-20 cos(\frac{\pi}{180}t)=-9

cos(\frac{\pi}{180}t)=\frac{9}{20}

and we can take the inverse of cos to get:

\frac{\pi}{180}t=cos^{-1}(\frac{9}{20})

which yields two possible answers: (see attached picture)

so

\frac{\pi}{180}t=1.104 or \frac{\pi}{180}t=5.179

so we can solve the two equations. Let's start with the first one:

\frac{\pi}{180}t=1.104

t =1.104(\frac{180}{\pi})

t=63.25s

and the second one:

\frac{\pi}{180}t=5.179

t=5.179(\frac{180}{\pi})

t=296.73s

so now we can build our possible intervals we can use to test the inequality:

[0, 63.25]  for a test value of 1

[63.25,296.73] for a test value of 70

[296.73, 360] for a test value of 300

let's test the first interval:

[0, 63.25]  for a test value of 1

-20 cos(\frac{\pi}{180}(1))+22>13

2>13 this is false

let's now test the second interval:

[63.25,296.73] for a test value of 70

-20 cos(\frac{\pi}{180}(70))+22>13

15.16>13 this is true

and finally the third interval:

[296.73, 360] for a test value of 300

-20 cos(\frac{\pi}{180}(300))+22>13

12>13 this is false.

We only got one true outcome which belonged to the second interval:

[63.25,296.73]

so the total time spent above a height of 13m will be:

196.73-63.25=233.48s

which is the same as:

233.48(\frac{1min}{60s})=3.84 min

see attached picture for the graph of the situation. The shaded region represents the region where the passenger will be higher than 13 m.

3 0
3 years ago
I would like to know how to get the correct answer for this.
shusha [124]
For a problem like this, we have to think logically

we know that 6 * some number in the thousands must equal 25 thousand something. Let's say we put 5 in that first spot, 6 * 5,000 is already 30,000 so that's wrong. If we go one lower, 6 * 4,000 is 24,000 and so now we can include the 287 knowing it will fit.

so 6 * 4287 = 25,722.

all we do now is fill in the blanks to match our answer.
3 0
3 years ago
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