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joja [24]
3 years ago
13

Pls help asapp picture attached

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The answer to your question is x = 50

Step-by-step explanation:

Data

∠1 = 110°

∠3 = 2x + 10

Process

1.- Angle ∠1 and angle 3 are vertical angles so, they measure the same.

                         ∠1 = ∠ 3

                        110 = 2x + 10

2.- Solve for x

Substract 10 in both sides

                        110 - 10 = 2x + 10 - 10

Simplify

                             100 = 2x

Divide by 2 both sides

                             100/2 = 2/2 x

Simplify and result

                                 50 = x                        

Olin [163]3 years ago
3 0

Answer:

50

Step-by-step explanation:

Angle 1 is 110.

Angle 3 is 2x plus 10.

Angle 1 and 3 are vertically opposite angles.

And vertically opposite angles r equal.

Which means, angle 1=angle 3,and angle 2=angke 4.

Here we only Need angle 2 and 3.

Angke 2= angle 3.

Which is 2x plus 10=110.

Therefore 2x=110-10=100

Therefore x = 100÷2=50

There u have it ma'am.

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(d) If the perimeter of a rectangle is 32, then the length is 13 and the width is 3.
Stells [14]

Answer:

  • length = 10
  • width = 6

Step-by-step explanation:

Any pair of dimensions that total 16 will give a rectangle with a perimeter of 32.

  P = 2(L +W)

  32 = 2(L +W)

  16 = L +W . . . . . . . divide by 2

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This is true for L = 13 and W = 3. It is also true for L = 10 and W = 6, or any other pair of dimensions x and (16-x).

8 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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3 years ago
If the point (x, y) is in Quadrant IV, which of the following must be true?
gayaneshka [121]

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4 0
2 years ago
The expressions 10/12(245b−365) and 2/3(3b+6) represent the lengths of the diagonals of parallelogram WXYZ. For what value of b
makkiz [27]

Answer:

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Step-by-step explanation:

Length of diagonals of a parallelogram = \frac{10}{12}(245b - 365) and \frac{2}{3}(3b+6)

If the given parallelogram is a rectangle,

Length of the diagonals will be equal in measure,

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245b - 365 = \frac{12}{10}\times \frac{2}{3}(3b+6)

245b - 365 = \frac{4}{5}(3b+6)

5(245b - 365) = 4(3b + 6)

1225b - 1825 = 12b + 24

1225b - 12b = 24 + 1825

1213b = 1849

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b = 1.52

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4 0
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