Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
The ladder is 10 ft long...
Answer:
The expression 1.02^(4+n) can be used because 1.02^4 * 1.02^2= 1.02^(4+n) AND this is option C.
Step-by-step explanation:
For 4 + N years = (1 + 2/100)^(4+N)
= 1.02 ^ (4+N)
Remember, that the number of years is increased by N and interest rate remain the same, and n is years, and which is now 4+ N.
1.2 pounds is the weight of 40 biscuits and the cost is $2.70.
Answer:
x^3-10x^2+x+120
Step-by-step explanation:
Assuming you mean roots -3, 5, 8
These happen when we have (x+3)(x-5)(x-8)=0
Expand this
(x^2-2x-15)(x-8)=0
=x^3-2x^2-15x-8x^2+16x+120
=x^3-10x^2+x+120
