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3 years ago

Simplify.

2 answers:

8 0

6a - (b - (3a - (2b + c + 4a - (a + 2b - c))))
6a - (b - (3a - (2b + c + 4a - a - 2b + c)))
6a - (b - (3a - (2b - 2b + 4a - a + c + c)))
6a - (b - (3a - (3a + 2c)))
6a - (b - (3a - 3a - 3c))
6a - (b - 3a + 3a + 3c)
6a - (b + 3c)
6a - b - 3c

x³ + x² - 25x - 25
x²(x) + x²(1) - 25(x) - 25(1)
x²(x + 1) - 25(x + 1)
(x² - 25)(x + 1)
(x² - 5x + 5x - 25)(x + 1)
(x(x) - x(5) + 5(x) - 5(5))(x + 1)
(x(x - 5) + 5(x - 5))(x + 1)
(x + 5)(x - 5)(x + 1)

36x² + 60x + 25
36x² + 30x + 30x + 25
6x(6x) + 6x(5) + 5(6x) + 5(5)
6x(6x + 5) + 5(6x + 5)
(6x + 5)(6x + 5)
(6x + 5)²

Shalnov [3]3 years ago

5 0

Answer:

12a-5b

Step-by-step explanation:

is the correct answer for the first question

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3 years ago

An angle in a triangle measures 138 °. The other two angles are congruent. Enter and solve an equation to find the x measure of

Juli2301 [7.4K]

Hey there! I"m happy to help!

The interior angles of a triangle add up to 180. We have 2 angles that have a value of x, so 2x+138=180.

We subtract 138 from both sides.

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3 years ago

I need help with this promblem it’s ALGEBRA 2!

AlekseyPX

Answer:

$(f\circ h)(2)=2$

Step-by-step explanation:

<u>Composite Function </u>

Given f(x) and h(x) real functions, the composite function named $(f\circ h)(x)$ is defined as:

$(f\circ h)(x)=f(h(x))$

It can be found by substituting h into f.

We are given the functions:

$f(x)=2x^2-9x+2$

$h(x)=x^2-4$

It's required to find $(f\circ h)(2)$

As defined above:

$(f\circ h)(x)=f(h(x))$

Thus:

$(f\circ h)(2)=f(h(2))$

Find h(2):

$h(2)=2^2-4=0$

h(2)=0

Now:

$(f\circ h)(2)=2(0)^2-9(0)+2$

$(f\circ h)(2)=2$

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3 years ago

Point T has coordinates (-3, 4). If it was reflected over the x-axls, what were the coordinates of its pre-image?

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Step-by-step explanation:

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3 years ago

7 divided by somethings equal 7.35

Dmitriy789 [7]

Let's translate it into an equation and then solve...

7/x = 7.35
x * 7/x = 7.35 * x
7 = 7.35x
7/7.35 = x
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So 7 divided by .9524 (rounded to the nearest ten thousandth) equals 7.35

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3 years ago