All categories

3 years ago

Please help STRUGGLING with math few math questions! Ty

Mathematics

2 answers:

-BARSIC- [3]3 years ago

6 0

Question 1:

F(x) and g(x) are like variables, just plug into the equation.

f(x) + g(x) = (x + 6) + (12x - 7)

x+6+12x-7 = 13x-1

Question 2: f(3) + g(-1)

You plug in the x-values into the equation, and then take the answer and add them together.

f(3) = 3+4

g(-1) = 12(-1)-6

f(3) = 7

g(-1) = -18

7 + (-18) = -11

Question 3:

This is similar to question 1, plug in the variables and simplify.

9x - (7x+3)

Remember to distribute the "-"

9x - 7x - 3

2x - 3

stiv31 [10]3 years ago

3 0

Answer:

Question 1. 13x-1

Question 2. -11

Question 2x-3

Step-by-step explanation:

You might be interested in

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this question, we have that:

$\pi = 0.21$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when $M = 0.03$ . So