Your first step should be to plug in the q and f values they give you. q being 20 and f being 16. From there you want to isolate 1/p by subtracting the 1/20 from both sides. You should be left with 1/p = 1/16 - 1/20. This will come out to be 1/80 or 0.0125. Now that one side is 1/p and the other is 1/80 you can multiply both sides by p in order to get 1=1/80 times p which means that p = 80 . Hope this helps
Answer:
y=4
Step-by-step explanation:
y-y1=m(x-x1)
y-4=0(x-2)
y-4=0
y=0+4
y=4
Put the equations in for r and c
p(c)=10x-(4x+15)
put the negaive in
10x-4x-15
6x-15
Answer is C
Another way to write this is:
x = 23y + 5
xy = 6732
Now plug in the first equation into the second:
(23y + 5)y = 6732
23y^2 + 5y - 6732 = 0
Either use quadratic equation or factor:
(y - 17)(23y + 396) = 0
y = 17 or -396/23
You know you can automatically eliminate the second y because it's negative and you need the two integers to multiply to a positive number (6732).
Plug y = 17 back into either equation (second might be easier):
17x = 6732
x = 396
