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tankabanditka [31]
3 years ago
12

An object moving in a straight line changes its velocity uniformly from 2m/s to 4 m/s over a distance of 12 m. What was its acce

leration? (A) 0.5 m/s^2 (B) 1 m/s^2 (C) 2 m/s^2 (D) 3 m/s^2
Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:A

Explanation:

Initial velocity, u = 2m/s

Final velocity, v = 4m/s

Distance covered, s = 12m

Acceleration, a = ?

Using

v² = u² + 2as

2as = v² - u²

a = v²-u²/2s

a = 4²-2²/2 x 12

a = 16-4/24

a = 12/24

a = 0.5m/s²

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Answer:

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3 years ago
Two electric charges, held a distance, d, apart experience an electric force of magnitude, F, between them. If one of the charge
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Answer:

When one of charge is doubled, the magnitude of the force between them gets doubled.

Explanation:

The electric force between two electric charges is given by :

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If one of the charges is doubled in magnitude while maintaining the same separation between the charges, q_1'=2q_1

New force becomes,

F'=k\dfrac{q_1'q_2'}{d'^2}

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When one of charge is doubled, the magnitude of the force between them gets doubled. Hence, this is the required solution.

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4 years ago
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algol13

Answer:

4.1 km/m

Explanation:

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