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umka2103 [35]
3 years ago
11

Two speakers face each other, and they each emit a sound of wavelength . One speaker is 180 out of phase with respect to the oth

er. If we separate the speakers by a distance 1.5, how far from the left-most speaker should we place a microphone in order to pick up the loudest sound? Ignore reflections from nearby surfaces.
A. 1/2 lambda
B. 0 lambda
C. lambda
D. 3/4 lambda
E. 1/4 lambda
Physics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:

C. lambda

Explanation:

Loudest sound is heard where path difference of sound wave coming from two sources will be either zero or integral multiple of wavelength . Here waves are already out of phase by 180° so at t = 0 , there is a path difference of λ /2 where λ is wavelength . So taking into account this fact , for constructive interference , path difference needed is odd multiple of λ /2

Distance between the sources = 1.5 λ .

If we place the microphone at λ , path difference between the waves coming from two sources reaching microphone = λ - 0.5λ = 0.5λ . Hence at the point constructive interference will take place .

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How do geologists construct the geologic column?​
Luda [366]

Answer:

They do this by joining pieces of different Rock sequences together from different places in the whole world.

Explanation:

Geologic columns are basically an arrangement of rock layers whereby the newest rocks are at the top while the oldest rocks will be at the bottom. Thus, it is like a timescale that's used to find the age of rock formation on the earth around the world.

3 0
3 years ago
An object is moving with constant non-zero velocity. Which of thw following statements about it must be true
hram777 [196]

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

5 0
3 years ago
A 3 kg object is moving along a horizontal surface. The kinetic energy of the object is increasing at a constant rate of 6 J/m;
Whitepunk [10]

To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.

For conservation of energy we have that work is equal to kinetic energy therefore,

W = KE

Fd = \frac{1}{2} mv^2

Here,

F = Force

d = Displacement

m = Mass

v= Velocity

At the same time we have the relation of

F = \frac{W}{d}

Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to

F = \frac{W}{d} = 6J/m

Applying Newton's Second Law

F = ma

6J/m = (3kg)a

a = 2m/s^2

In 4 seconds final velocity of the object becomes

v = at

v= 2*4

v= 8m/s

Then the work done is equal to,

W = KE

W = \frac{1}{2} mv^2

W = \frac{1}{2} (3)(82)

W = 96J

Then the displacement is,

W = F*d

d = \frac{W}{F}

d = \frac{96}{6}

d = 16 m

Therefore the distance moved is 16m

7 0
4 years ago
El monoxido de carbono reacciona con el hidrogeno gaseoso para producir metanol (ch3oh) calcule el reactivo limite y el reactivo
Orlov [11]

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH  

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

\eta_{CO} = \frac{m}{M}              

En donde:    

m: es la masa

M: es el peso molecular  

\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles

\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles      

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.    

\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles

m = 0,071 moles*32,04 g/mol = 2,27 g

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!      

6 0
3 years ago
Which requires more work, increasing a car's speed from 0 mph to 30 mph or from 50 mph to 60 mph?
Gnom [1K]

Increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

<h3>What is work?</h3>

Work is a measure of energy expended in moving an object. It is calculated by multiplying the force by the distance.

According to this question, work is required to move a car from one position to another.

The distance moved from 0 - 30mph is more than that moved from 50 - 60mph, therefore, increasing a car's speed from 0 mph to 30 mph requires more work than that of 50 mph to 60 mph.

Learn more about work at: brainly.com/question/19382352

#SPJ1

8 0
2 years ago
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