Give me points I will help you
<h2>
Answer:</h2>
(a) 10.00V
(b) 0.5V
<h2>
Explanation:</h2>
(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;
P = V² / R ------------------(i)
From the question;
P = 5.00W
R = 20.00Ω
Substitute these values into equation (i) as follows;
5.00 = V² / 20.00
V² = 5.00 x 20.00
V² = 100.00
V = 
Solve for V;
V = 10.00V
Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V
(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;
V = I x R
=> I = V / R ----------------(ii)
Substitute the values of V and R into equation (ii) as follows;
I = 10.00 / 20.00
I = 0.5A
Therefore, the current through the resistor is 0.5A
For both cases we will use the proportional values of the distance referring to the amplitude and intensity. Theoretically we know that the intensity is inversely proportional to the square of the distance, while the amplitude is inversely proportional to the distance, therefore,
PART A ) Intensity is inversely proportional to the square of the distance

Therefore the intensity of the two values would be


PART B) Amplitude is inversely proportional to the distance


