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ELEN [110]
2 years ago
7

All my digits are different.The sum of my digits is 24.Rounded to the nearest 100,I am 1000,but rounded to the nearest 10.I am 9

90. what number am i?
Mathematics
1 answer:
IRISSAK [1]2 years ago
8 0
The answer is 987

9 + 8 +7 = 24

nearest 100 is 1000
nearest 10 is 90
so 987
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Zinaida [17]

Answer:

  y = -1000x +11000

Step-by-step explanation:

<u>Given:</u>

  (x, y) = (sales price, number sold) = (3, 8000), (6, 5000)

<u>Find</u>:

  slope-intercept equation for a line through these points

<u>Solution</u>:

When given two points, it often works well to start with the 2-point form of the equation for a line.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Filling in the given points, you have ...

  y = (5000 -8000)/(6 -3)/(x -3) +8000

  y = (-3000/3)(x -3) +8000

  y = -1000x +3000 +8000 . . . . eliminate parentheses

  y = -1000x +11000 . . . . the desired equation

6 0
3 years ago
(16-24)-(57-77)÷(-2)<br>​
sergey [27]
( 16-24)-(57-77)÷(-2)
= -8-(-20)÷-2
= -8+20÷-2
= -18

Answer -18 <<<
3 0
3 years ago
Expand and simplify (x+6)(x−11)
KatRina [158]

Answer:

x^2 - 5x - 66

Step-by-step explanation:

1. Distrubute the x to the x and -11 so you will get x^2 - 11x

2. Distrubute the 6 to x and -11 and you get 6x - 66

3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66

7 0
1 year ago
A point is chosen randomly on PS. Identify the probability that the point is on RS. Help, please?!
dimulka [17.4K]

d. 11/13

is the correct answer

7 0
3 years ago
Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b
Elenna [48]

Answer:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Step-by-step explanation:

We want to verify the identity:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }

Collect LCM

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }

We simplify the RHS to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}

We rationalize to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}

We expand to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}

Factor negative one in the denominator:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}

Apply the Pythagoras Property to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}

Simplify to get:

\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}

Or

\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}

Divide both the numerator and denominator by sin x

\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}

This finally gives:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

8 0
2 years ago
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