Answer:
Answer b of the first one
answer of q9
Step-by-step explanation:
(x+iy)(2−3i)=4+i
2x−(3x)i+(2y)i−3yi
2
=4+i
Real
2x+3y
+
Imaginary
(2y−3x)
i=4+i
Comparing the real & imaginary parts,
2x+3y=4--------------------------(1)
2y−3x=1----------------------------(2)
Solving eq(1) & eq(2),
4x+6y=8
−9x+6y=3
13x=5⇒x=
13
5
y=
13
14
∴(x,y)=(
13
5
,
13
14
)
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SIMILAR QUESTIONS
star-struck
If e
x+iy
=α+iβ, then x+iy is called logarithm of α+iβ to the base e.∴log
e
(x+iy)=log
e
(re
iθ
) =log
e
r+iθ where r is modulus value of x+iy & θ be the argument of x+iy If i
α+iβ)
=α+iβ, then α
2
+β
2
equals
Hard
View solution
>
The modulus of (1 + i) (1 + 2i) (1 + 3i) is equal to
<h3>
Answer: Choice D) 0.0285</h3>
=========================================
Explanation:
You move the decimal point two spots to the left to go from 2.85% to 0.0285
Or you can think of it like this:
2.85% = (2.85)/100 = 0.0285
since "percent" means "per 100"
Answer: 7 cubic meters
Step-by-step explanation:
you add
Answer:
equation of line is:
y = -2x - 6
Step-by-step explanation:
hope this helps
There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.
Solving for small c..

So it's the answer shown in the picture, but it should be a capital W instead of a lowercase w.