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denis-greek [22]
3 years ago
9

1.75 = 12.3 - x / 2.8 Solve for x

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0
1.75=12.3-x/2.8
x=(12.3-1.75)2.8
x=29.54
Sati [7]3 years ago
6 0
1.75 = 12.3 - x / 2.81.75-12.3=-x/2.8

-10.55=-x/2.8

-10,55*-2.8=x

x=29.54
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Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5.<br> b^2+3(2x-y)
butalik [34]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

b^{2}+3(2x-y) = 3^{2} + 3 (2(4)-5) .

Now we need to solve 3^{2} + 3 (2(4)-5).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3^{2} + 3 (2(4)-5)

First, calculate 3 to the power of 2 and get 9.

9+3(2\times 4-5)=18

Multiply 2 and 4 to get 8.

9+3(8-5) =18  

Subtract 5 from 8 to get 3.    

9+3\times 3 =18  

Multiply 3 and 3 to get 9.

9+9 =18.

<h2>And the answer is, you guessed it, 18!</h2>

7 0
2 years ago
I NEEDDD HELPPP ITSSSSSS URGENTTTTT!!!
Georgia [21]
Answer:

100 degrees

Step-by-step explanation:

measure of FHD = 65 + 35

measure of FHD = 100
6 0
3 years ago
Read 2 more answers
How can i find the answer to 188x31?
eduard
The answer to 188x31 is 5,828
7 0
3 years ago
Karen has gallons of apple juice and gallons of orange juice in her refrigerator. How many gallons of juice does Karen have alto
3241004551 [841]
E. All of the above
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7 0
3 years ago
Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²
Ludmilka [50]

Answer:

<h3>\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \:  {units}^{2} }}}}}</h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

\sf{ =  \frac{2.89 + 8.59 + 8.6}{2} }

\sf{ =  \frac{20.08}{2} }

\sf{ = 10.04}

∆ ABD = \sf{ =  \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }

\sf{  = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}

\sf{  =  \sqrt{149.8891} }

\sf{ = 12.2429}

For ∆ ACD ,

\sf{s =  \frac{8.6 + 4.3 + 7.58}{2} }

\sf{ =   \frac{20.48}{2} }

\sf{ = 10.24}

∆ ACD = \sf{ =  \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }

\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }

\sf{ =  \sqrt{265.3456} }

\sf{ = 16.2894}

Area of quadrilateral ABCD = \sf{12.2429 + 16.2894}

\sf{ = 28.5323}

\sf{ = 28.53} units ²

Hope I helped!

Best regards!

8 0
3 years ago
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