I would want to round to the nearest hundred place rather than the nearest tens place because if you round to the nearest hundred place then your answer would be closer to the original answer.
Answer:
Vertical: G an B. Adjacent: C and F. Supplementary: A and E. Straight: A, E. Complementary: G , B and E,A.
Answer:
greater etext they'd hereafter greatest note count defective justification
The area of the surface given by
is 1. In terms of a surface integral, we have

By multiplying each component in
by 5, we have

and the same goes for the derivative with respect to
. Then the area of the surface given by
is

Answer:
B
Step-by-step explanation:
let the angles be 3k,10k,2k
then 3k+10k+2k=180
15k=180
k=180/15=12
x=10k=10×12=120°