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2 years ago

G(x) =3x-1 find g(-4)

Mathematics

1 answer:

ira [324]2 years ago

6 0

First plug in -4 for g to get 3(-4)-1. 3(-4) equals -12, and -12-1 equals -13.

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What is 12 divided by 1230 in long division

Bess [88]

It is 102.5. You made it kind of confusing at first by putting the divisor first in your question then putting your dividend, but I understand what you meant.

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3 years ago

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Please help me with this Geometry Proof ASAP - IMAGE ATTACHED - THANKS

blondinia [14]

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3 years ago

What fraction is equivalent to 3/10 and has a denominator of 100

rosijanka [135]

Answer:

30/100

Step-by-step explanation:

This should be relatively easy since if the denominator is 100 then x/100 has to = 3/10

Since the denominator 10 has to be 100, you multiply by 10.

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7 0

2 years ago

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Complete the slope equation of the line through (-4,8) and (4,4)

olya-2409 [2.1K]

Answer:

-1/2

Step-by-step explanation:

We can find the slope if we are given two points

m = (y2-y1)/(x2-x1)

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Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter

Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and $\sqrt{8^{2} - x^{2} }$ or $\sqrt{64 - x^{2} }$

thus tan(arcsin(x/8)) = $\frac{x}{\sqrt{64 - x^{2} }}$ =

Therefore ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)

Here we have cos = adjacent/hypotenuse where adjacent side is $\sqrt{64 - x^{2} }$ and hypothenuse = 8 we have $\sqrt{64 - x^{2} }$ /8

B . cos (arsin (x/8)) ....sqrt(64-x^2)/8

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2 years ago