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yarga [219]
3 years ago
10

What is the value of 2x^-2y^-2 for x = 3 and y = 2? a) 1/18 b) 72 c) 2(-6)^-4 d) 1/648

Mathematics
1 answer:
sladkih [1.3K]3 years ago
8 0
2x^-2y^-2 = 2/x^2y^2 = 2/(2)^2 x (3)2 = 2/4 x 9 = 2/36 = 1/18
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What is the value of this expression when<br> d= 47 and f = 3?<br> 6 (d - f) +f
agasfer [191]

Answer:

267

Step-by-step explanation:

We are given the expression:  6 (d - f) +f

The value of the expression when d= 47 and f = 3 is :

6 (47 - 3) +3 = 6×(44) + 3 = 264 + 3 = 267

=267

7 0
2 years ago
Two competing headache remedies claim to give fast-acting relief. An experiment was performed to compare the mean lengths of tim
DaniilM [7]

Answer:

t = 0.875

Step-by-step explanation:

Given

<u>Brand A</u>            <u>Brand B</u>

n_ 1= 12               n_2 = 12

\bar x_1 = 21.8            \bar x_2 = 18.9

\sigma_1 = 8.7              \sigma_2 = 7.5

Required

Determine the test statistic (t)

This is calculated as:

t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} +  \frac{1}{n_2}}}

Calculate s using:

s = \sqrt{\frac{(n_1-1)*\sigma_1^2+(n_2-1)*\sigma_2^2}{n_1+n_2-2}}

The equation becomes:

s = \sqrt{\frac{(12-1)*8.7^2+(12-1)*7.5^2}{12+12-2}}

s = \sqrt{\frac{1451.34}{22}}

s = \sqrt{65.97}

s = 8.12

So:

t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} +  \frac{1}{n_2}}}

t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{12} + \frac{1}{12}}}

t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{6}}}

t = \frac{21.8 - 18.9}{8.12 * 0.408}}

t = \frac{2.9}{3.31296}}

t = 0.875

3 0
3 years ago
What does i^739 equal? explain how you found your answer.
Sophie [7]
<h3>Answer:   -i</h3>

========================================================

Explanation:

i = sqrt(-1)

Lets list out the first few powers of i

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = i*i^2 = i*(-1) = -i
  • i^4 = (i^2)^2 = (-1)^2 = 1

By the time we reach the fourth power, we repeat the cycle over again (since i^0 is also equal to 1). The cycle is of length 4, which means we'll divide the exponent over 4 to find the remainder. Ignore the quotient. That remainder will determine if we go for i^0, i^1, i^2 or i^3.

For example, i^5 = i^1 because 5/4 leads to a remainder 1.

Another example: i^6 = i^2 since 6/4 = 1 remainder 2

Again, we only care about the remainder to find out which bin we land on.

-------------

Turning to the question your teacher gave you, we have,

739/4 = 184 remainder 3

So i^739 = i^3 = -i

<h3>-i is the final answer</h3>

--------------

Side notes:

  • if i^a = i^b, then a-b is a multiple of 4
  • Recall that the divisibility by 4 trick involves looking at the last two digits of the number. So i^739 is identical to i^39.
4 0
2 years ago
Can someone do this for me ahhhh
Aleksandr [31]
28:13 is the answer i’m pretty for sure
4 0
3 years ago
What is 22 3/4÷2 as a fraction,?<br>​
nordsb [41]

Answer:

11375 / 1000

Hope This Helps!      Have A Nice Day!!

4 0
2 years ago
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