What is the value of 2x^-2y^-2 for x = 3 and y = 2? a) 1/18 b) 72 c) 2(-6)^-4 d) 1/648
1 answer:
2x^-2y^-2 = 2/x^2y^2 = 2/(2)^2 x (3)2 = 2/4 x 9 = 2/36 = 1/18
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Havent done this in years but i think it would just be 12