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2 years ago

Please help with this math problem

Mathematics

2 answers:

stepladder [879]2 years ago

6 0

Answer:

-15

Step-by-step explanation:

Given:

x=-7
-14+7=x+8

Simply plug in and see if the statement is true. If not, isolate x.

Test for truth:

-14+7=-7+8
-7=1
NOT true.

Isolate x in original equation:

-14+7=x+8
-14+7-8=x
-7-8=x
-15=x

pantera1 [17]2 years ago

4 0

B. X=-15

Step-by-step explanation:-14+7=-7 and -15+8=-7

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Drag the numbers to order them from least to greatest. -5/8 -7/9 -4/5 -3/7

nataly862011 [7]

Answer:

- 0.8, -0.777, - 0.625, - 0.428

Step-by-step explanation:

-0,625, -0.777, -0.8, - 0,428

8 0

2 years ago

Y = −3x <br> x + y = −4<br> Solution system

Verizon [17]

Answer:

Step-by-step explanation:

Y = - 3x. Equation 1

x + y = - 4 equation 2

Putting value of y

x + (-3x) = - 4

x - 3x = - 4

-2x = - 4

x = - 4/-2 = 2

Putting value of x in the equation 1

Y = - 3(2)

Y = - 6

7 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

(4x1,000)+(5x100)+(9x10)+(2x1)+(7x1/10) in standard form

Igoryamba

Answer:

4592.7

Step-by-step explanation:

Add them up:

4000 + 500 + 90 + 2 + 0.7 = 4592.7

6 0

2 years ago

Please help with this quesriom

Wittaler [7]

Answer:

True

Step-by-step explanation:

Just a guess

6 0

2 years ago