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anygoal [31]
2 years ago
9

M is the midpoint of segment CS. C is at (-8, 2) M is at the origin. What are the coordinates of S?

Mathematics
1 answer:
ahrayia [7]2 years ago
4 0
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)

C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)

a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8

b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2  and y₂ = -2

Then the coordinates of  S are S(8 , -2)
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\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

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As the value of the second factor is:

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And the product value is:

y=\frac{28}{25}=1.12

It is clear that the product value 'y = 1.12' is lesser than the second factor value '1.4'.

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