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3 years ago

The domain of the following relation: R: {(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)} is:

2 answers:

4 0

The domain of the given set of numbers are the values of abscissa. From the given the values of the abscissa are: -3, 5, 1, 2. Therefore, the answer to this item is letter A. 5 need not be written twice.

Shalnov [3]3 years ago

3 0

Answer:

For an ordered pair (x,y) that a set contain :

x = Domain of the relation

y = Range of the relation

In a relation x can have two or more than two ranges i.e a x can have more or more than two images.

So, Domain = First element of ordered pair that the following relation R contains ={(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)}= -3, 5, 1,2,5

But the element 5 is Occuring twice.

Domain = { -3,1,2,5} →→Option A

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Add a comment

3 Answers

Consider the following Argand-diagram

enter image description here

The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is

x+yi

To figure out θ, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let θ be the angle formed with the real axis.

tanθ=yx

⟹tan−1(yx)

The hypotenuse of the triangle will be

x2+y2−−−−−−√

Therefore,

Step-by-step explanation:

5 0

3 years ago

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

5 0

3 years ago

Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte

Tpy6a [65]

Answer:

$3\frac{13}{20}=3.65$ kg.

Step-by-step explanation:

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are $2\frac{1}{4}$ kg.