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kupik [55]
3 years ago
12

I don't know what the answer to this is plzz help

Mathematics
2 answers:
poizon [28]3 years ago
7 0
7x3x2 and 7x6x1.
Hope this helps!
rodikova [14]3 years ago
3 0
Number 1 is: 7x3x2

Number 2 is: 6x7x0


Hope this helped you :D
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How many shapes would I have on term 104?​
pishuonlain [190]

Answer:

313 shapes

Step-by-step explanation:

The nth term is 3n+1

so 3x104=312+1= 313 shapes

4 0
3 years ago
What is 244 divided by 60 with remainders
Troyanec [42]
244 divided by 60 = 4.0666
3 0
3 years ago
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I’ll give Brainly but pleaseee help
77julia77 [94]
Fruit adult = 26
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8 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
Solve<br> -3x - y = 8<br> - 7x + 3y = -24
Nookie1986 [14]
The solution is (0,-8)
7 0
3 years ago
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