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kupik [55]
3 years ago
12

I don't know what the answer to this is plzz help

Mathematics
2 answers:
poizon [28]3 years ago
7 0
7x3x2 and 7x6x1.
Hope this helps!
rodikova [14]3 years ago
3 0
Number 1 is: 7x3x2

Number 2 is: 6x7x0


Hope this helped you :D
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Can someone figure out the problem in this image?
erma4kov [3.2K]
Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)

Re-write both sides:
3^(4x-5) = 3^(-6x - 30)

from here, you can solve x 

4x - 5 = -6x - 30
4x + 6x = -30 + 5
10x = -25
    x = -2.5
7 0
3 years ago
Which pairs make the equation x-9y=12 true
Serggg [28]

Answer:

(12,0), (3, -1) (0,-4/3)

Step-by-step explanation:

To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.

6 0
3 years ago
No clue how to do this
andreev551 [17]

B is your awnser! sorry if im wrong my calc shows its without a  - symbol

7 0
3 years ago
An investor plans to invest $500 a year and expects to get a 10.5% return. If the investor makes these contributions at the end
taurus [48]

The present value of the investment is $6000.

According to the statement

Principal amount = $500

and Return amount = 10.5%

Time period = 20 years.

Now we find the present value of money then

By the formula

PV = P[1-(1+r)^n]/r

PV = 500[1-(1+0.10)^20]/0.10

PV = 6000

So, The present value of the investment is $6000.

Learn more about Return Amount here brainly.com/question/2456547

#SPJ1

4 0
1 year ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
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