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Sholpan [36]
3 years ago
9

Please help need answers now !

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

(2x -4) (Find your answer) then add your answers and divide it by 180

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I have no clue what that is
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Can a pair of lines be both parallel and skew?
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3 years ago
A sailboat is sitting at rest near its dock. A rope attached to the bow of the boat is drawn in over a pulley that stands on a p
irina [24]

Answer:

The boat is approaching the dock at rate of 2.14 ft/s

Step-by-step explanation:

The situation given in the question can be modeled as a triangle, please refer to the attached diagram.

A rope attached to the bow of the boat is drawn in over a pulley that stands on a post on the end of the dock that is 5 feet higher than the bow that means x = 5 ft.

The length of rope from bow to pulley is 13 feet that means y = 13 ft.

We know that Pythagorean theorem is given by

x^{2} + y^{2} = z^{2}

Differentiating the above equation with respect to time yields,

2x\frac{dx}{dt}  + 2y\frac{dy}{dt} = 2z\frac{dz}{dt}

x\frac{dx}{dt}  + y\frac{dy}{dt} = z\frac{dz}{dt}

dx/dt = 0  since dock height doesn't change

y\frac{dy}{dt} = z\frac{dz}{dt}

\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}

The rope is being pulled in at a rate of 2 feet per second that is dz/dt = 2 ft/s

First we need to find z

z² = (5)² + (13)²

z² = 194

z = √194

z = 13.93 ft

So,

\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}

\frac{dy}{dt} = \frac{13.93}{13}(2)

\frac{dy}{dt} = 2.14 ft/s

Therefore, the boat is approaching the dock at rate of 2.14 ft/s

8 0
2 years ago
Sally can paint a room in 7 hours while it takes Steve 4 hours to paint the same room. How long would it take them to paint the
crimeas [40]
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4 0
2 years ago
2x2 + 7x + 3 = 0 i need help
ratelena [41]

Answer:

x=-\frac{1}{2},-3

Step-by-step explanation:

8 0
2 years ago
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