Answer:
Part a.)
C = 3N
Note: Any variables could be used in this equation. It is important
that the students be able to define them.
Part b.)
3c + 750 = 1200 (or equivalent representation)
‐750 ‐750
3c = 450
c = 150
750 + 3c ≥ 1200
‐750 ‐750
3c ≥ 450
c ≥ 150
Parts c. and d.)
3(200) + 750 = T
600 + 750 = T
1350 = T
Step-by-step explanation:
plssss give brainliest and thanks
-7 = e/4 + 14
-7 - 14 = e/4
-21 = e/4
-21 × 4 = e
-81 = e
~Hope I helped!~
I believe this problem is true.