Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
interesting choice of pfp
Exponential function is characterized by an exponential increase or decrease of the value from one data point to the next by some constant. When you graph an exponential function, it would start by having a very steep slope. As time goes on, the slope decreases until it levels off. The general from of this equation is: y = A×b^x, where A is the initial data point at the start of an event, like an experiment. The term 'b' is the constant of exponential change. This is raised to the power of x, which represents the independent variable, usually time.
So, the hint for you to find is the term 500 right before the term with an exponent. For example, the function would be: y = 500(1.8)^x.
Answer: 45/1637
Explanation:
Simplify:
90/3274 = 45/1637
Answer:
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Step-by-step explanation: