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Alina [70]
3 years ago
11

A graph has time (years) on the x-axis and height (inches) on the y-axis. A line goes through points (2, 5) and (4, 10).

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

2.5 inches per year

Step-by-step explanation:

We can deduce the rate of change by obtaining the slope or gradient of thw points given :

Gradient = Rise / Run.

Point A (2, 5) ; point B (4, 10)

x1 = 2 ; y1 = 5 ;x2 = 4 ; y2 = 10

Rise = y2 - y1 = 10 - 5 = 5

Run = x2 - x1 = 4 - 2 = 2

Rate of change = Gradient = 5 /2 = 2.5

Which is 2.5 inches per year

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The selling price of a​ refrigerator, is ​$ 796.40 . If the markup is 10 % of the​ dealer's cost, what is the​ dealer's cost of
8_murik_8 [283]

The final price (what it is selling for) is $796.40

The markup is 10% of the original price (the dealer's cost) , meaning that it is 10% more.

We need to find the original price.

We write this as an equation

The original price *110% = final price

This is because the original price is itself (100%) added with 10%

Plug in the known final price

Original Price * 110% = 796.40

Convert 110% to a decimal because the other numbers- such as the final price are also decimal numbers.

Convert 110% to a decimal by moving the decimal point up 2 spaces ( basically dividing it by 100)

110% = 1.1

So it is now

Original price *1.1 = 796.40

Divide both sides by 1.1 to isolate our unknown, the original price

Original price = $724

5 0
3 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
3 years ago
ASAPPP!!!!!
Sergio039 [100]

Answer:

185

Step-by-step explanation:

45 +70(2) = 185

5 0
3 years ago
I need the answers for these pls help
DanielleElmas [232]

Answer:

1)

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

2)

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

  • The measure of an central angle is equal to the measure of its subtended arc
  • The measure of a circle is 360°
  • Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
  • If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

1)

In circle O

A.

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

B.

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

C.

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

D.

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

2)

1]

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

2]

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

8 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues. 5 - 15 + 45 - 135 + ...
nalin [4]

Answer:

<em>summation of five times negative three to the power of n from n equals zero to infinity</em>

Step-by-step explanation:

<u>Summation Notation </u>

It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:

5-15+45-135+...

If we take 5 as a common factor, we have

5(1-3+9-27+...)

The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1

The summation is then represented by

\sum_{n=0}^{\infty}5(-3)^n

This corresponds with the option:

<u>summation of five times negative three to the power of n from n equals zero to infinity</u>

8 0
3 years ago
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