Ray MO bisects LMN LMO = 6x-20 and NMO =2x+36. solve for x and find LMN
2 answers:
6x - 20 = 2x + 36
6x - 2x = 36 + 20
4x = 56
x = 56/4
x = 14
m∠LMN = 6x - 20 + 2x + 36 = 8x + 16 = 8 * 14 + 16 = 128°
6x - 2x = 36 + 20
4x = 56
x = 56/4
x = 14
m∠LMN = 6x - 20 + 2x + 36 = 8x + 16 = 8 * 14 + 16 = 128°
Answer: The required value of x is 14 and the maesure of angle LMN is 128 degrees.
Step-by-step explanation: As given in the question and shown in the attached figure below, ray MO bisects angle LMN.
Also,
We are to find the value of x and the measure of angle LMN.
Since ray MO bisects angle LMN, so we must have
And, we get
Thus, the required value of x is 14 and the maesure of angle LMN is 128 degrees.
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