1. A relation is a set from x to a set y is called a function if each element of c is related to exactly one element in y. That is,given an element c in c, there is only one element in y that x is related to.
2. You can set up the relation as a table of ordered pairs. Then, text to see if each element in the domain is matched with exactly one element in the range . if so you have a function
3. The domain is the set of all possible x-values which will make the function "work" and will output real y- values .When finding the domain , remember :the denominator (bottom) of a fraction cannot be zero .
4.
The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation

This gives

Evaluate the products

Evaluate the like terms

So, we have
f(x) = x²+ 2/3x - 1/9
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Answer: 178.31
Step-by-step explanation: subtract 574.54 by 396.23
Answer:
2x^2+14x+5
Step-by-step explanation:
x^2+9x+5x+5
Combine Like Terms:
=2x^2+9x+5x+5
=(2x^2)+(9x+5x)+(5)
=2x^2+14x+5
The other solution to the absolute value equation 3 − 2|0.5x + 1.5| = 2 is x = -4
<h3>How to determine the solution?</h3>
The equation is given as:
3 − 2|0.5x + 1.5| = 2
Subtract 3 from both sides
-2|0.5x + 1.5| = -1
Divide both sides by -2
|0.5x + 1.5| = 0.5
Expand the equation
0.5x + 1.5 = 0.5 or 0.5x + 1.5 = -0.5
Subtract 1.5 from both sides
0.5x = -1 or 0.5x = -2
Divide both sides by 0.5
x = -2 or x = -4
Hence, the other solution to the absolute value equation 3 − 2|0.5x + 1.5| = 2 is x = -4
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