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stiv31 [10]
3 years ago
13

Divide 9x^2 by 18y^2

Mathematics
2 answers:
Neporo4naja [7]3 years ago
3 0

Step-by-step explanation:

√9x2√18y2. √9=3. √x2=x. √18=√9×2=3√2. √y2=y. Therefore √9x2√18y2=3x3√2y = x√2y.

mr_godi [17]3 years ago
3 0

Answer:

A. \frac{x \sqrt{2} }{2y}

Step-by-step explanation:

\sqrt{9 {x}^{2} }  \div  \sqrt{18 {y}^{2} }  \\  \\ =   \frac{ \sqrt{9{x}^{2} }  }{ \sqrt{18 {y}^{2} } }  \\  \\  =  \sqrt{ \frac{9 {x}^{2} }{18 {y}^{2} } }  \\  \\  \\  =  \sqrt{ \frac{ {x}^{2} }{2 {y}^{2} } }  \\  \\  =  \frac{x}{ \sqrt{2} y}  \\  \\  =  \frac{x \sqrt{2} }{2y}

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Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
3 years ago
Somebody please help asapppppp
anzhelika [568]
The function was moved two units to the left (a)
8 0
3 years ago
Read the instructions
nordsb [41]

Answer:

Step-by-step explanation:

\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}

Multiply the equation by 4

4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

5x = 6y + 4

5x - 6y = 4 --------------------(I)

\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\

Multiply the equation by 6

6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\

2*(7y + 3) = 3x + 2*7

14y + 6 = 3x + 14

14y = 3x + 14 - 6

14y = 3x + 8

-3x + 14y = 8 ------------------------(II)

Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3              15x - 18y = 12

(II)*5           <u>-15x  + 70y = 40</u>     {Now add}

                          52y = 52

                              y = 52/52

                            y = 1

Substitute y =1 in equation (I)

5x - 6*1 =  4

5x - 6 = 4

      5x = 4 +6

      5x = 10

         x = 10/5

x = 2

7 0
3 years ago
The expression is equivalent to the expression
mamaluj [8]

Answer: False

Step-by-step explanation:

For this to be true; x must be squared.

4 0
3 years ago
Pls help i am in k12
suter [353]

Answer:

image not good

Step-by-step explanation:

7 0
3 years ago
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