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2 years ago

Someone help me find the Pythagorean Theorem for these please¿?

Mathematics

2 answers:

dezoksy [38]2 years ago

4 0

For number 1, theat is not a right triangle as a squared plus b squared does not equal c squared

My name is Ann [436]2 years ago

3 0

The pythagorean theorem is when you take side A and square it. then you take side b and square it. add side a and side b together and square side c. if side a and b equal side c than it is a right triangle

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9 1/3 divided by 2/3

Citrus2011 [14]

14 is the correct answer

6 0

2 years ago

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Please help have no clue<br><br><br> c8q6

Aleksandr-060686 [28]

Answer:

the tan of 36° = 0.726

Step-by-step explanation:

if you go on your calculator an press tan then 36 it gives you the answer

3 0

3 years ago

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If ∠a = 90°, find the measures of ∠b, ∠c and ∠d.

nydimaria [60]

Answer:

m∠b = 35°

m∠c = 145°

m∠ d = 35°

Step-by-step explanation:

To find m∠b, we use Definition of Supplementary Angles:

180 - (90 + 55) = 35°

To find m∠c, we also use Definition of Supplementary Angles:

180 - 35 = 145°

To find m∠d, we use Vertical Angles Theorem:

m∠b = m∠d = 35°

5 0

2 years ago

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Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0

3 years ago

Rewrite the expression (19x3 – 5x2 + 6x – 2)/(x + 1) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remainder, and b

wolverine [178]

We are asked to perform the long division on the following expression.

$\frac{(19x^3-5x^2+6x-2)}{(x+1)}$

Let us perform the long division.

So, we have

Quotient: q(x) = 19x^2 - 24x + 30

Remainder: r(x) = -32

Divisor: b(x) = x + 1

Therefore, the equivalent expression is

$19x^2-24x+30-\frac{32}{(x+1)}$

The 3rd option is the correct answer.

7 0

11 months ago