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polet [3.4K]
2 years ago
13

What is the LCM of 3 and 7

Mathematics
2 answers:
Dima020 [189]2 years ago
6 0

Answer:

The LCM of 3 and 7 is 21.

Step-by-step explanation:

‎‎‎‎‎‎

aivan3 [116]2 years ago
6 0

Answer:

21

Step-by-step explanation:

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5/2x-7=2/4x+14<br><br>a x = -6<br>b x = 6<br>c x = 8<br>d x = 12​
kykrilka [37]
The answer I got was x= 21/2
3 0
2 years ago
Diane has a hospital appointment. when she arrives at the hospital, the car park is nearly full. there are a total of 534 car pa
Oksanka [162]
In total there are 534 spaces, but 476 are occupied.
Occupied spots cannot be parked in.
The answer is 534 - 476, which equals 58 available spots. 
4 0
2 years ago
If C(m) = 0.50m + 30 represents the cost of renting a car, how many miles were driven if cost is $130
FinnZ [79.3K]

Answer:

m=#miles

so 130= .5m+30

subtract 30 from each side

100$= .5m than divide .5 to isolate m

m= 200

Step-by-step explanation:

3 0
3 years ago
What is the solution set to, "Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each da
Anastaziya [24]

Answer:

Katie will collect more than 100 seashells in 5 and a half days.

Step-by-step explanation:

Katie already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach.

Let x be the number of days Katie is collecting seashells.

In x days, she will collect 12x seashells.

In total, she will collect 34+12x seashells.

Katie wants to collect over 100 seashells, so

34+12x> 100

Solve this inequality. Subtract 34:

34+12x-34>100-34\\ \\12x>66\\ \\2x>11\\ \\x>5 \dfrac{1}{2}

Katie will collect more than 100 seashells in 5 and a half days.

3 0
3 years ago
If a and b are both positive, two-digit integers, is a + b a multiple of 11? The tens digit of a is equal to the units digit of
Serhud [2]

Answer:

Yes!

Step-by-step explanation:

Let x be the tens place and y be the units place. x and y need to be odd because in other case a or b will not be odd. For example, if x=1 and y=2 a will be 21 but b will be 12 that is not odd.

Now, a+b = xy+yx. Note that xy is not x*y, is just the digits concatenated.Then, there are two cases:

If x+y<10 then xy+yx = (x+y)(x+y) (again, that is not a multiplication is x+y concatenated with x+y) and that is 11*(x+y) a multiple of 11.

If x+y≥10 then xy+yx = (x+y+1)(x+y-10) because x+y<20.

Now we are going to see that last result without the concatenation, as a sum, that is

(x+y+1)*10 + x+y-10 = 10x+10y+10+x+y-10 = 11x+11y = 11(x+y). This result is clearly a multiple of 11.

In conclusion, in all cases the result of a+b is a multiple of 11.

6 0
3 years ago
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