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Yuri [45]
3 years ago
12

Factorise fully 3 x + 15

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

3(x+5)

Step-by-step explanation:

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Help me! i have 20 minutes​
KIM [24]

Your on your own.. :/

5 0
3 years ago
Kelly plants 45 tulips in 30 minutes what is the unit rate?
Natasha_Volkova [10]

Answer:

1.5 per minute

Step-by-step explanation:

unit rate is how many in 1 minute so 45 divided by 30 is 1.5 and if you want to check your answer do 1.5 x 30 which is 45

7 0
3 years ago
In France gasoline is 2.096 per liter. There are 3.78541178 liters per gallon. If the Euro is trading at 1.762 then the equivale
Lana71 [14]

Answer:

equivalent price/ gallon = 13.98 US$ / gallon

Step-by-step explanation:

Assuming that the exchange rate is 1.762 US$ /€ , then

thus

equivalent price/ gallon =   liters/gallon * euros / liter * dollars/euro

equivalent price/ gallon = 3.78541178 liters/ gallon *  2.096 € /liter * 1.762 US$ /€ = 13.98 US$ / gallon

equivalent price/ gallon = 13.98 US$ / gallon

if the actual price would be different from the equivalent , then there would be an arbitrage opportunity ( profit with no risk)

4 0
4 years ago
How long will it take for $2500 to double if it is invested at 6% annual interest compounded 6 times a year? Enter exact calcula
12345 [234]

Answer:

Part 1) t=11.610\ years

Part 2) t=11.552\ years

Step-by-step explanation:

Part 1) we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06\\n=6  

substitute in the formula above

5,000=2,500(1+\frac{0.06}{6})^{6t}  

2=(1.01)^{6t}  

Apply log both sides

log(2)=log[(1.01)^{6t}]

log(2)=(6t)log(1.01)  

solve for t

t=log(2)/[6log(1.01)]  

t=11.610\ years

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06  

substitute in the formula above

5,000=2,500(e)^{0.06t}

2=(e)^{0.06t}  

Apply ln both sides

ln(2)=ln[(e)^{0.06t}]

ln(2)=(0.06t)ln(e)

ln(2)=(0.06t)

t=ln(2)/(0.06)

t=11.552\ years

3 0
3 years ago
Given: 8-2y – 3y -9=-11<br> Prove: y = 2
astraxan [27]
Step 1: group Y on left side
(-2 - 3)y = -5y

step 2: group constants on left side
8 - 9 = -1

step 3: form modified equation
-5y - 1 = 11

step 4: group constants
-5y - 1 + 1 = -11 + 1

step 5: cancel 1 on left side
-5y = -10

step 6: divide each side by -5
-5y/-5 = -10/-5

answer: y = 2
3 0
3 years ago
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