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Yuri [45]
3 years ago
12

Factorise fully 3 x + 15

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

3(x+5)

Step-by-step explanation:

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Select the correct answer.
iris [78.8K]

Answer:

Hi,

Step-by-step explanation:

Answer D

2x^6y²

7 0
2 years ago
Evaluate the series:<br> 2-10+50-250..., n=8
garik1379 [7]

The sum of first 8 terms of series is -130208

<em><u>Solution:</u></em>

Given that,

2 - 10 + 50 - 250 , ....

n = 8

Find the common ratio between a term and its previous term

r = \frac{-10}{2} = -5\\\\r = \frac{-250}{50} = -5

Thus common ratio is same

This is a geometric series

<em><u>The sum of terms of geometric sequence is given as:</u></em>

S_n = \frac{a_1(1-r^n)}{1-r}

Where,

r is the common ratio

n is the nth term

a_1 is the first term of series

From series,

a_1 = 2\\\\r = -5\\\\n = 8

Therefore,

S_8 = \frac{2 \times (1 - (-5)^8)}{1-(-5)}\\\\S_8 = \frac{2 \times (1-390625)}{6}\\\\S_8 = -130208

Thus sum of first 8 terms of series is -130208

6 0
4 years ago
Find the common difference of the arithmetic sequence 20,18,16,...
Liono4ka [1.6K]

Answer:

It goes down by 2 every time so -2 i'm pretty sure

8 0
3 years ago
A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
Somebody help with the correct answer please
Maslowich
D. Exponential Growth
6 0
3 years ago
Read 2 more answers
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