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3 years ago

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What are the Respiratory organs?

2 answers:

gogolik [260]3 years ago

6 0

<span>Mouth,Pharynx,Larynx.Trachea,Bronchi and Bronchioles,Lungs,<span>Muscles of Respiration.</span></span>

DerKrebs [107]3 years ago

5 0

There are 3 major parts of the respiratory system: the airway, the lungs<span>, and the muscles of respiration. The airway, which includes the </span>nose<span>, </span>mouth<span>, </span>pharynx,larynx<span>, </span>trachea<span>, </span>bronchi<span>, and bronchioles, carries air between the </span>lungs<span> and the body's exterior. and the lungs </span>

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A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo

Black_prince [1.1K]

The work done by the car at the given mass and speed is $3.1 \times 10^5 \ J$

The given parameters;

<em>First distance traveled by the car, s = 72 km</em>
<em>Second distance traveled, = 90 km</em>
<em>Total time of motion, t = 2 hours</em>
<em>Total mass = 2.5 x 10³ kg</em>

The initial velocity of the car, u = 72 km/h = 20 m/s

The final velocity of the car, v = 90 km/h = 25 m/s

The acceleration of the car is calculated as follows;

$a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v- u}{t_2 - t_1} \\\\$

the initial time of motion, t₁ = 1 hour = 3600 s

the second time of motion, t₂ = 1 hour + 1 hour = 2 hours = 7200 s

$a = \frac{25-20}{7200 - 3600} \\\\a = 0.00138 \ m/s^2$

The force exerted by the car is calculated as follows;

$F = ma\\\\F = (2.5 \times 10^3) \times 0.00138 \\\\F = 3.45 \ N$

The work done by the car is calculated as follows;

$W = F\times s$

where;

<em>s is the displacement of the car</em>

$s = (72 - 0) \ k m \ + \ (90 - 72) \ km\\\\s = 90 \ km = 90,000 \ m$

$W = 3.45 \times 90,000 \\\\W = 3.1 \times 10^5 \ J$

Thus, the work done by the car at the given mass and speed is $3.1 \times 10^5 \ J$ .

Learn more about work done here: brainly.com/question/19498865

4 0

2 years ago

Please check if my answer is correct

emmasim [6.3K]

Answer:

Yep! it's correct might need to double check tho

4 0

3 years ago

Read 2 more answers

There are___<br> periods included in the periodic table.

Maurinko [17]

The answer to your question is 7

5 0

4 years ago

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Which definition best describes the encoded message you worked with in this activity? Explain.

lisov135 [29]

Answer:

Explanation:

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3 years ago

Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temp

yuradex [85]

Answer:

2*10^9electrons

Explanation:

Remember that the net force will be zero at terminal voltege so

Mg = 6πrng

At 35v

We have

qvr = 6πrng

q= 6 x 3.142* nx 2.6*10^-5/35

q,= 3.2x 10^ - 10C

So using n= q/e

= 3.2x 10^ - 10C/1.6*10-19

= 2*10^9electrons

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3 years ago