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Tanya [424]
3 years ago
10

Which astronomer desighed scientific instruments, inclubing a nrw kind of thetmometer, an improved compass? and a more powerfull

telescope?
Physics
1 answer:
Alla [95]3 years ago
4 0
Galileo Galilei is the man that invented the stuff
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PLEASE HELP ASAP 36. The Doppler Effect applies to light in addition to sound. What do you call the phenomenon that causes dista
skad [1K]

Answer:

It's probably the Redshift and Blueshift

Explanation:

The light shifting towards shorter or longer wavelengths as objects in space (stars or galaxies) move closer or farther away from us. This phenomenon is known as the Redshifts and Blueshifts. The concept indicates us that the Universe is expanding.

Hope this helps you!

Bye!

3 0
3 years ago
आप शोर मत करिए। किस प्रकार का वाक्य है- *​
Law Incorporation [45]

Answer:

477547748jkdsjdjk

Explanation:

7 0
3 years ago
Find the expression for the displacement covered in nth or in last one second​
Natali [406]

Answer:

Snth = u + a/2 ( 2n - 1)

Explanation:

Do you need explanation based on graph, integration or other method?

3 0
3 years ago
Part 1 :
dybincka [34]

Answer:

1. 218.55 N

2. 30.96^{o}

3. 2.1 m/s^{2}

Explanation:

Part 1;

Net force F=mg sin \theta where m is mass, g is gravitational force and \theta is the angle of inclination

F= 46*9.8*sin 29^{o}= 218.55N

Frictional force, F_{r} is given by

F_{r} = \mu_{s}mg cos \theta where \mu_{s} is the coefficient of static friction

F_{r} = 0.6*46*9.8 cos 29

F_{r}=236.57N

Since F_{r}>F, therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force F_{s} = \mu_{s} mg cos \theta

mg sin \theta =\mu_{s} mg cos \theta

\mu_{s}= \frac {sin \theta}{cos \theta}

\mu_{s}= tan \theta

The maximum angle of inclination \theta = tan^{-1} \mu_{s}

\theta = tan^{-1} (0.6)

\theta= 30.96^{o}  

        

Part 3:

Net force on the object is given by

ma = mg sin 38 - \mu_{k} mg cos 38 where \mu_{k} is the coefficient of kinetic friction

 a = g ( sin 38 - \mu_{k} cos 38 )

                 = 9.8 ( sin 38 - (0.51) cos 38 )

                = 2.1m/s^{2}

7 0
3 years ago
A sand core used to form the internal surfaces of a steel casting experiences a buoyancy force of 225 n. the volume of the mold
pashok25 [27]

Newton’s second law gives us the relationship of force F, mass m and acceleration a. The formula is given as:

<span>F = m a                  --> 1</span>

However we also know that the relationship of mass m, density ρ, and volume V is:

<span>m = V ρ                 --> 2</span>

Therefore substituting equation 2 to equation 1:

F = ρ V a = ρ V g

where a is acceleration due to gravity, ρ is density of water and V is the volume of the casting, therefore:

F = (1x10^-3 kg/cm^3) (4840 cm^3) (9.8 m/s^2)

F = 47.432 kg m/s^2

F = 47.432 N

 

Going back to equation 1:

47.432 N = m (9.8 m/s^2)

m = 4.84 kg

 

<span>Hence the weight of the final casting is 4.84 kg</span>

5 0
3 years ago
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