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LuckyWell [14K]
3 years ago
11

If i have a mass of 58.0 kilograms what is my weight

Physics
1 answer:
liraira [26]3 years ago
7 0
You would be 127.86 lbs. approx. One kilogram is equal to 2.20 pounds, so you just multiply kilos into the conversion rate. If you are trying to convert pounds to kilos, divide your pounds into the conversion rate.

Hope that helped! :)
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A block of mass 8 m can move without friction
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Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

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In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance
maw [93]

Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = X_{L} = j\omega L = 2\pi fL

where

R = resistance

X_{L} = Inductive Reactance

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

C = \frac{\epsilon_{o}A}{x}

where

x = separation between the parallel plates

Thus

C ∝ \frac{1}{x}

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

Also,

Z ∝ I

Therefore,

\frac{Z}{I} = \frac{Z'}{I'}

\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}

{R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})

{R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})

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X_{C} = 4R

6 0
3 years ago
A successful marriage is based on:
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Answer:

a and d

Explanation:

4 0
2 years ago
Read 2 more answers
"5 N, up" is an example of a ___.<br> OA) force<br> OB) mass<br> OC) weight<br> OD) magnitude
Sunny_sXe [5.5K]

Answer:

A) Force

Explanation:

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5 0
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