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4 years ago

7

Problem page the length of a rectangle is four times its width. if the perimeter of the rectangle is 70 cm , find its area.

1 answer:

agasfer [191]4 years ago

5 0

So we can call the width of the rectangle x.
So then the length would be 4x.
The perimeter would then be 10x.
Since the perimeter is 70, we can say 70 = 10x.
And then simplify that to 7 = x.
So the length of a rectangle would be 28 cm, and the width would be 7.
So to find the area, just multiply length by width.
28*7 = 196 square cm
So the rectangle's area is 196 square cm.

I hope I helped!

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3 years ago

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3 years ago

Pls help:Find all the missing elements:

Yuliya22 [10]

Answer:

<h3>B = 48.7° , C = 61.3° , b = 12</h3>

Step-by-step explanation:

In order to find B we must first angle C

To find angle C we use the sine rule

That's

$\frac{ |a| }{ \sin(A) } = \frac{ |c| }{ \sin(C) }$

From the question

a = 15

A = 70°

c = 14

So we have

$\frac{15}{ \sin(70) } = \frac{14}{ \sin(C) }$

$\sin(C) = \frac{14 \sin(7 0 ) }{15}$

$C = \sin^{ - 1} ( \frac{14 \sin(70) }{15} )$

C = 61.288

<h3>C = 61.3° to the nearest tenth</h3>

Since we've found C we can use it to find B.

Angles in a triangle add up to 180°

To find B add A and C and subtract it from 180°

That's

A + B + C = 180

B = 180 - A - C

B = 180 - 70 - 61.3

<h3>B = 48.7° to the nearest tenth</h3>

To find b we can use the sine rule

That's

$\frac{ |a| }{ \sin(A) } = \frac{ |a| }{ \sin(B) }$

$\frac{15}{ \sin(70) } = \frac{ |b| }{ \sin(48.7) }$

$|b| = \frac{15 \sin(48.7) }{ \sin(70) }$

b = 11.9921

<h3>b = 12.0 to the nearest tenth</h3>

Hope this helps you

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