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Nikolay [14]
3 years ago
5

3x^2-3x ----------- -3 x^2-9x please give me the simplified answer + explanation

Mathematics
1 answer:
STatiana [176]3 years ago
8 0
You want us to simplify \frac{3x^2-3x}{x^2-9x}-3


first, factor top and bottom
3x^2-3x=3x(x-1)
x^2-9x=x(x-9)

so we have
\frac{3x(x-1)}{x(x-9)}-3=
\frac{3(x-1)}{x-9}-3
we want to combine fractions so multiply 3 by \frac{x-9}{x-9}
\frac{3(x-1)}{x-9}-\frac{3(x-9)}{x-9}=
\frac{3(x-1)-3(x-9)}{x-9}=
\frac{3x-3-3x+27}{x-9}=
\frac{24}{x-9}


the simplified answer is \frac{24}{x-9}
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