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kap26 [50]
3 years ago
9

Solve the system by graphing. 1-3x - y = -10 [4x – 4y = 8

Mathematics
1 answer:
sineoko [7]3 years ago
6 0

change the first to

3x + y = 10

and the second to

x - y = 2

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50% because there are originally 18 chips in the bag and 9 of them are pink. After drawing a pink chip, she replaces it and draws again (still a 50% chance).

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3 years ago
Suppose that 16% of the population of the U.S. is left-handed. If a random sample of 170 people from the U.S. is chosen, approxi
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Answer:

0.6064 = 60.64% probability that fewer than 29 are left-handed.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

16% of the population of the U.S. is left-handed.

This means that p = 0.16

Sample of 170 people

This means that n = 170

Mean and standard deviation:

\mu = E(X) = np = 170*0.16 = 27.2

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{170*0.16*0.84} = 4.78

Probability that fewer than 29 are left-handed.

Using continuity correction, this is P(X < 29 - 0.5) = P(X < 28.5), which is the pvalue of Z when X = 28.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{28.5 - 27.2}{4.78}

Z = 0.27

Z = 0.27 has a pvalue of 0.6064

0.6064 = 60.64% probability that fewer than 29 are left-handed.

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