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3 years ago

12

What is the product in lowest terms?

1 answer:

JulsSmile [24]3 years ago

3 0

Multiply the numerators and denominators together:

-40/156

Divide the numerator and denominator by 4:

-10/39

You might be interested in

Can someone help me with this question 2x+3=15 is x

MArishka [77]

Answer:

x=6

Step-by-step explanation:

2x+3=15

subtract 3 on both sides

2x=12

x=6

7 0

4 years ago

Read 2 more answers

Circular tracts of land with diameters 900 meters, 700 meters and 600 meters are tangent to each other externally. There are hou

Rudik [331]

Answer:

$\alpha=69.28^o$

$\beta=61.26^o$

$\gamma=49.46^o$

<em /> $A=227980.26\ m^2$ <em />

Step-by-step explanation:

<u>Triangle Solving</u>

If we had a triangle will its three sides of known length, we can solve for the rest of the parameters of the triangle, i.e. the area, perimeter and internal angles.

The three circles have diameters 900 m, 700 m and 600 m and are tangent to each other externally. The distances from their centers (where houses are located) are the sum of each pair of the radius of the circles. Thus, the sides of the triangle are

$x=450+350=800$

$y=450+300=750$

$z=350+300=650$

The internal angles can be computed by using the cosine's law

$x^2=y^2+z^2-2yzcos\alpha$

$y^2=x^2+z^2-2xzcos\beta$

$z^2=x^2+y^2-2xycos\gamma$

Where \alpha, \beta and \gamma are the opposite angles to x, y and z respectively. Solving for each one of them:

$\displaystyle cos\alpha=\frac{y^2+z^2-x^2}{2yz}$

$\displaystyle cos\alpha=\frac{750^2+650^2-800^2}{2\cdot 750\cdot 650}$

$cos\alpha=0.3538$

$\alpha=69.28^o$

Similarly

$\displaystyle cos\beta=\frac{x^2+z^2-y^2}{2xz}$

$\displaystyle cos\beta=\frac{800^2+650^2-750^2}{2\cdot 800\cdot 650}$

$cos\beta=0.4808$

$\beta=61.26^o$

The other angle is computed now

$\displaystyle cos\gamma=\frac{x^2+y^2-z^2}{2xy}$

$\displaystyle cos\gamma=\frac{800^2+750^2-650^2}{2\cdot 800\cdot 750}$

$cos\gamma=0.65$

$\gamma=49.46^o$

The area can be found by

$\displaystyle A=\frac{1}{2}x.y.sin\gamma$

$\displaystyle A=\frac{1}{2}\cdot 800\cdot 750\cdot sin49.46^o$

$A=227980.26\ m^2$

8 0

3 years ago

Find the probability that a Type A bulb lasts at least 300 hours and a Type B bulb lasts at least 400 hours.

barxatty [35]

Answer:

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

Step-by-step explanation:

We require more information by I will explain in principle:

If Type A has at least 300 hours and Type B at least 400 hours.

$(X>3)(Y>4)=P(X>3)P(X>4)$

You need to determine the Probability density function of X and Y and then subtract 1 from both

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

This will give you the probability of the expression.

5 0

4 years ago

You time someone completing a single task the first time at 100 minutes and the fourth time they do the task it takes 81 minutes

kolezko [41]

Answer:

given statement is false

Step-by-step explanation:

given data

first time = 100 minutes

fourth time = 81 minutes

solution

as here time for 1st unit is multiply by learning percentage for obtain time for 2nd unit

so here time for 2nd unit divide by time of 1st unit so 100 is here learning curve

so $\frac{81}{100}$ × 100 = 81 percent

but it say 90 percent learning curve

so given statement is false

3 0

3 years ago

Is this answer correct

Kobotan [32]

Yes, that looks right.

6 0

4 years ago