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insens350 [35]
3 years ago
11

Find the probability that a Type A bulb lasts at least 300 hours and a Type B bulb lasts at least 400 hours.

Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))

Step-by-step explanation:

We require more information by I will explain in principle:

If Type A has at least 300 hours and Type B at least 400 hours.

(X>3)(Y>4)=P(X>3)P(X>4)

You need to determine the Probability density function of X and Y and then subtract 1 from both

P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))

This will give you the probability of the expression.

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210

Step-by-step explanation:

Here comes the problem from Combination.

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