Question

Find the probability that a Type A bulb lasts at least 300 hours and a Type B bulb lasts at least 400 hours.

Answer 1

Answer:

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

Step-by-step explanation:

We require more information by I will explain in principle:

If Type A has at least 300 hours and Type B at least 400 hours.

$(X>3)(Y>4)=P(X>3)P(X>4)$

You need to determine the Probability density function of X and Y and then subtract 1 from both

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

This will give you the probability of the expression.