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3 years ago

Find the probability that a Type A bulb lasts at least 300 hours and a Type B bulb lasts at least 400 hours.

Mathematics

1 answer:

barxatty [35]3 years ago

5 0

Answer:

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

Step-by-step explanation:

We require more information by I will explain in principle:

If Type A has at least 300 hours and Type B at least 400 hours.

$(X>3)(Y>4)=P(X>3)P(X>4)$

You need to determine the Probability density function of X and Y and then subtract 1 from both

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

This will give you the probability of the expression.

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3 years ago

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Given:

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To find:

The measure of the angle opposite the side of length 8.

Solution:

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2 years ago

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Step-by-step explanation:

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