All categories

3 years ago

Find the probability that a Type A bulb lasts at least 300 hours and a Type B bulb lasts at least 400 hours.

Mathematics

1 answer:

barxatty [35]3 years ago

5 0

Answer:

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

Step-by-step explanation:

We require more information by I will explain in principle:

If Type A has at least 300 hours and Type B at least 400 hours.

$(X>3)(Y>4)=P(X>3)P(X>4)$

You need to determine the Probability density function of X and Y and then subtract 1 from both

$P(X>3)P(X>4)=(1-F_1(3))(1-F_2(4))$

This will give you the probability of the expression.

You might be interested in

PLEASE HELP

Anastasy [175]

Answer:

the answer is 67 coins are not Nickels

Step-by-step explanation:

29+24+16=67 so there is 27 Nickels in the jar

4 0

3 years ago

True or false 798.7 divided by 1,000= 7.987

aleksandrvk [35]

False. 798.7 divided by 1000 is 0.7987 because 1000 has three zeros, so you move the decimal point three units/numbers to the left

False. 73.09 divided by 100 is 0.7309, you are not multiplying by 100

False. 75.04 divided by 10 is 7.504, you are not multiplying by 10

3 0

3 years ago

Read 2 more answers

Now, think about multiplying-25×-35.

Aliun [14]

Answer:

Positive

Step-by-step explanation:

If you multiply both negative, it will always result to positive.

Rule:

+ × + = +

+ × - = -

- × + = -

- × - = +

5 0

3 years ago

Please someone answer this please

gladu [14]

Option C:

$\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

To find which expression is equivalent to the given expression.

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

Using exponent rule: $\frac{1}{a^m}=a^{-m}, \ \ \frac{1}{a^{-m}}=a^{m}$

$$=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }$

$$=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }$

Using exponent rule: ${a^m}\cdot{a^n}=a^{m+n}$

$$=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }$

$$=\frac{-18 a^{2} b^{11}}{-12 }$

Divide both numerator and denominator by the common factor –6.

$$=\frac{3 a^{2} b^{11}}{2 }$

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }$

Therefore, $\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Hence Option C is the correct answer.

8 0

3 years ago

Mini made a recipe that yields 4 and 1 over 2 cups. If each serving is 1 over 2 cup, which expression will help Mini determine t

Katarina [22]

4 and 1 over 2 <span> ÷ 1 over 2</span>

6 0

3 years ago

Read 2 more answers