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seraphim [82]
3 years ago
14

The volume of a rectangular prism with a square base is 180 in3. Its height is 5 in. Find the length of the edge of the square b

ase.
Mathematics
1 answer:
amid [387]3 years ago
4 0

Answer:

l = 6 inches

Step-by-step explanation:

We have,

The volume of a rectangular prism with a square base is 180\ in^3.

Height of the prism is  5 in

It is required to find the length of the edge of the square base. Let it is l.

The formula of the volume of the rectangular prism is given by :

V=l\times b\times h

A is area of base of prism

It has a square base, l =b

V=l^2\times h\\\\l=\sqrt{\dfrac{V}{h}} \\\\l=\sqrt{\dfrac{180}{5}} \\\\l=6\ in

So, the length of the  edge of the square base is 6 inches.                  

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After production, an electrical circuit is given a quality score of A, B. C, or D. Over a certain period of time, 77% of the cir
Tanzania [10]

Answer:

a) 0.0125

b) 0.4579

Step-by-step explanation:

For this question use tree diagram method to solve the question or by simply listing down the probabilities as I have done in the attached picture. Firstly, we need to convert all percentages in to decimal and those decimals will represent probability of each event. For example if we consider probability of quality score A it can be found by diving 77 with 100:

77/100 = 0.77

Similarly all probabilities can be found by simply dividing percentages with 100.

Part (b) is a conditional probability question. Given that a circuit failed is the condition. So we need to use conditional probability method to solve it.

7 0
4 years ago
Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are social science majors, and 12 are ne
seraphim [82]
A) Suppose J is the set of juniors and S is the set of social science majors. There are 35 students in all, but 12 of them don't belong to either set, so |J\cup S|=35-12=23. Then

|J\cap S|=|J|+|S|-|J\cup S|=17+20-23=14

So the probability that a random student is both a junior and social science major is \mathbb P(J\cap S)=\dfrac{14}{35}

b) We're looking for the probability \mathbb P(S\mid J). By definition, this would be


\mathbb P(S\mid J)=\dfrac{\mathbb P(S\cap J)}{\mathbb P(J)}=\dfrac{\frac{14}{35}}{\frac{17}{35}}=\dfrac{14}{17}
7 0
3 years ago
What is the easiest way to solve this problem?<br> thank u!!
RoseWind [281]

Answer:

B. 2

Step-by-step explanation:

\frac{2(x + 1)}{x + 5}  = 1 -  \frac{1}{x + 5}

Multiply two sides by (x+5), we have

(x + 5)   \frac{2(x + 1)}{x + 5} = (x + 5) - (x + 5)  \frac{1}{x + 5}

so

2(x + 1) = x + 5 - 1  \\  =  >  \: 2x + 2 = x + 4 \\  =  > x = 2

6 0
4 years ago
Read 2 more answers
A. As you walk to your car, you notice that your tire is nearly flat! The initial psi level yesterday was 40 but it is now only
Sveta_85 [38]

Answer:

Step-by-step explanation:

A) initial psi level = 40

Today, psi level = 38

Amount by which it decreased is 40 - 38 = 2 psi

Percentage by which it reduced is

2/40 × 100 = 5% or 0.05

The exponential model expression is

A = (1 - r)^t

where

A represents the final value after t days

P represents the initial value

r represents the rate of decrease

Therefore, when t = 7, then

A = 40(1 - 0.05)^7

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Log 3 = t log 1.0125

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t = 0.477/0.0054t

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3 0
3 years ago
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Answer:

80⁰

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