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tresset_1 [31]
3 years ago
9

Can some one help me with theses and explain how u got the answers and u have to zoom in to see it

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0
Y < 4x - 2......u have a slope of 4.....u have a y int (where the line crosses the y axis) at (0,-2)......and u have a < sign....meaning it is a dashed line shaded below the line

and if u want to find ur x int (where the line crosses the x axis) sub in 0 for y and solve for x...disregarding the inequality sign
y = 4x - 2
0 = 4x - 2
-4x = -2
x = -2/-4
x = 1/2.....so ur line crosses the x axis at (1/2,0)

so ur graph is : graph 3
========================
y > -x + 3.....u have a slope of -1....u have a y int at (0,3)....ur inequality sign is >....meaning it is a dashed line, because there is no equal sign...and it is shaded above the line since it is greater then

ur x int is :
y = -x + 3
0 = -x + 3
x = 3......x int at (3,0)

ok..I am having a problem with this one because none of ur graphs match this inequality...because ur line will cross the x axis at 3...and none of ur graphs show this
===================
y < -2......when u have y = a number (or <,>) this will be a horizontal line....it will go thru -2 all the way across....and since it has a < sign, it will be a dashed line with shading under the line.
so ur graph is : graph 2


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lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

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<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

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Answer:

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hope this helped

Step-by-step explanation:

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